Wednesday, 27 July 2011
To make a hypothesis
First, you must understand that a hypothesis is a statement that relates a manipulated variable with a responding variable.
Therefore, you must be able to identify the manipulated variable and the responding variable for an experiment.
For example, in experiment to determine the effect of temperature on the rate of reaction between sodium thiosulphate and sulphuric acid.
The manipulated variable is temperature, and the responding variable is rate of reaction.
Therefore, the statement of hypothesis is: When the temperature of sodium thiosulphate increases, the rate of reaction with sulphuric acid increases.
Monday, 25 July 2011
Operational Definition
For example, the operational definition for coagulation of latex:
The "what you do" is... when acid is added to latex..
The "what you observe " is.... white solid is formed.
Therefore the operational definition for the coagulation of latex is ..When acid is added to latex, white solid is formed. (SPM 2008)
The operational definition for the neutralisation of acid or alkali could be... When acid is added to alkali with a few drops of phenolphthalein, the pink solution changes to colourless.
The operational definition for the reactivity of Group 1 elements towards water:
When a metal which is lower down in Group 1is put into a basin filled with water, the movement of the metal on the water surface is faster // more vigorous// the flame produced is bigger or brighter.
Teacher Norini hopes that you girls and boys have some idea now the meaning of operational definition. Well, you can always ask Teacher Norini if you don't.
Friday, 22 July 2011
Constructs in Paper 3
For example, making hypothesis, aim @ problem statement, naming variables, to state the operational definition and so on.
Question for the day!
What is operational definition?
For example: Give the operational definition for the neutralisation of acid and alkali.
Teacher Norini will give the answer later....
Monday, 18 July 2011
Difference in pH value between hydrochloric acid and ethanoic acid.
1. Hydrochloric acid is a strong acid.
2. Therefore, acid can ionise completely in water
3. to produce high concentration of hydrogen ion
4. Ethanoic acid is a weak acid.
5. This acid can ionise partially in water
6. to produce low concentration of hydrogen ion
7. When the concentration of hydrogen ion is higher, the pH value is lower
Salam boys and girls!
Hydrochloric acid 1.0 mol dm-3 has 2 pH value.
Ethanoic acid 1.0 mol dm-3 has 6 pH value.
Explain the difference in pH value for the acids
Sunday, 17 July 2011
Ok, the answer to why alloy is harder than its's pure metal is:
1. Atoms of foreign element added to metal are of different size from atoms in pure metal.
2. These atoms will disrupt the orderly arrangement of the atoms in metal.
3. When force is applied, the foreign atoms will reduce the sliding of the atoms over each other.
4. Thus making alloy harder and stronger.
Pure metal is soft, malleable and ductile because:
1. Atoms are of the same size
2. Atoms are arranged in layers and orderly manner.
3. When force is applied the layers of atoms can easily slide over each other
Note: make sure you know how to draw the diagram for the arrangement of atoms in alloy and pure metal
Wednesday, 13 July 2011
Tuesday, 12 July 2011
More homework on Chemical Formulae and Equations
Element | Mg | O |
Mass (g) | ||
Number of moles | ||
Simplest ratio of moles | ||
Empirical Formula |
Homework for the weekend
- 13.5 g C. 54.0 g
- 27.0 g D. 108.0 g
- 0.03 C. 0.08
- 0.05 D. 0.09
- 39 C. 78
- 69 D. 110
Element | M | O |
Mass/g | 5.6 | 2.4 |
Relative atomic mass | 56 | 16 |
- M2O3 C. MO2
- M2O D. MO
Element | Relative atomic mass |
X | 24 |
M | 12 |
m | Y | |
A | 2 | Hydrogen - 1 |
B | 12 | Carbon - 12 |
C | 14 | Nitrogen - 14 |
D | 16 | Oxygen - 16 |
Sunday, 8 May 2011
Saturday, 7 May 2011
SALTS
By NORINI BT JAAFAR
1.Definition: Salt is an ionic compound formed when the H+ ion in an acid is replaced by a metal ion or an ammonium, NH4+ ion.
e.g. HCl + NaOH → NaCl + H2O
2. Salts can be classified into two main groups shown in Figure 1.
SALTS
Soluble Insoluble
Figure 1
3. (a) Effects of heat on carbonate salts.
Carbonate salt → Metal oxide + CO2
Δ
Example: Heating of copper(II) carbonate.
Chemical equation: CuCO3 → CuO + CO2
Observations: i. Green solid of copper(II) carbonate turns black solid of copper(II)
oxide.
ii. Gas passed through lime water will turn lime water chalky.
Other examples: (a) PbCO3 → PbO + CO2
Observations: i. Lead(II) oxide, PbO deposit is orange when hot, turns yellow when
cooled.
ii. Lime water turns chalky.
(b) ZnCO3 → ZnO + CO2
Observations: i. Zinc oxide, ZnO deposit is yellow when hot, turns white when cooled.
ii. Lime water turns chalky.
Note: All carbonates salt will be decomposed by heat to produce metal oxide and carbon dioxide except sodium carbonate, Na2CO3 and potassium carbonate, K2CO3 which cannot be decomposed by heat.
3(b) Effects of heat on nitrate salt.
Nitrate salt → metal oxide + NO2 + O2
Δ
Example: Heating of lead(II) nitrate, Pb(NO3)2.
Chemical equation: 2Pb(NO3)2 → 2PbO + 4NO2 + O2
Observations: i. Lead(II) oxide, PbO deposit is orange when hot, turns yellow when
cooled.
ii. When glowing wooden splinter is put inside the test tube, it
rekindles.
Oxygen, O2 gas produced.
iii. Brown gas released turns damp blue litmus paper to red.
Nitrogen dioxide, NO2 gas produced.
Other examples: 2Zn(NO3)2 → 2 ZnO + 4NO2 + O2
2Cu(NO3)2 → 2 CuO + 4NO2 + O2
Note: Sodium nitrate, NaNO3 and potassium nitrate, KNO3 when heated will decompose to produce nitrite salt and oxygen gas.
2NaNO3 → 2NaNO2 + O2
2KNO3 → 2KNO2 + O2
4. Preparation of Soluble Salts
Soluble salts can be prepared by the following methods:
(i) Neutralization reaction: Acid + Alkali → Salt + H2O
This method is suitable for sodium, potassium and ammonium salts.
(ii) Acids + Metal → Salts + H2
This method is not suitable for salts when the metal is below hydrogen in the
Electrochemical Series, e.g copper.
(iii) Acid + Metal Oxide → Salt + H2O
(iv) Acid + Metal Carbonates → Salt + H2O + CO2
Example: To
prepare of copper(II) sulphate salt
Substances: copper(II) oxide, sulphuric acid 1.0 mol dm-3 solution.
Materials: beaker, 250 ml, filter funnel, glass rod, filter paper, evaporating dish, Bunsen burner, tripod stand, wire gauze.
Procedures:
- Pour (50 – 100) cm3 of sulphuric acid solution into a beaker.
- Heat the acid.
- Copper(II) oxide powder is added into the acid until excess (to ensure that all the acid has completely reacted).
- Stir the mixture.
- Filter the mixture to remove the excess copper(II) oxide powder.
- Transfer the filtrate to an evaporating dish and heat the solution until saturated.
(To ensure the solution is saturated, dip a glass rod into the solution and take out. If there are crystals formed at the glass rod, this shows that the solution is saturated)
- Cool the saturated solution to room temperature.
- Filter the salt crystals formed and dry the salt with filter paper.
- Chemical equation: CuO + H2SO4 → CuSO4 + H2O
5. Preparation of insoluble salts.
Insoluble salts can be prepared by the precipitation or the double decomposition method. The general equation:
Salt solution of X + Salt solution of Y → Insoluble salt XY + Salt solution
Example: Pb(NO3)2 + 2NaCl → PbCl2 + 2NaNO3
(White precipitate)
Ionic equation: Pb2+ + 2Cl- → PbCl2
Example: To prepare silver chloride salt (an insolube salt)
Substances: silver nitrate solution, sodium chloride solution.
Apparatus: beaker, glass rod, filter funnel, evaporating dish, filter paper.
Procedures:
- (30 – 50) cm3 of silver nitrate solution is poured into a beaker.
- (30 – 50) cm3 of sodium chloride solution is added into the beaker.
- Stir the mixture.
- Filter the white precipate formed.
- Wash the residue (white precipitate) with distilled water.
- Dry the white powder with filter paper.
- Chemical equation: AgNO3 + NaCl → AgCl + NaNO3
- Ionic equation: Ag+ + Cl- → AgCl
- White salt of siver chloride formed.
Tips: When you are required to prepare a salt, the first thing to do is to determine whether the salt to be prepared is soluble or insoluble. Then choose the suitable method to prepare the salt.
6. Numerical Problems Related to Salts.
Example: Excess zinc is added to 50 cm3 of sulphuric acid solution 1.0 mol dm-3 .
The chemical reaction is shown below:
Zn + H2SO4 → ZnSO4 + H2.
Calculate the mass of zinc sulphate salt formed from the reaction.
[ Relative atomic mass: O, 16, S, 32; Zn, 65;]
Solution: From the equation, 1 mol of H2SO4 ≡ 1 mol of ZnSO4
Number of moles of H2SO4 given = MV
1000
= 1.0 x 50
1000
= 0.05
Therefore, mass of ZnSO4 = 0.05 x (65 + 32 + 4(16))
= 8.05 g
Exercise
Objective Questions:
- Which of the following salts is not soluble in water?
A Sodium carbonate
B Silver nitrate
C Lead(II) chloride
D Zinc sulphate
- Which of the following equations is correct for the preparation of copper(II) sulphate?
A Cu(NO3)2 + Na2SO4 → CuSO4 + 2 NaNO3
B Cu(OH)2 + H2SO4 → CuSO4 + 2H2O
C Cu + H2SO4 → CuSO4 + H2
D CuCO3 + H2SO4 → CuSO4 + H2O + CO2
- When substance X is heated strongly, a type of gas and a black deposit were produced. The gas released turns lime water chalky. Which of the following is substance X?
A Copper(II) oxide
B Lead(II) carbonate
C Copper(II) carbonate
D Zinc carbonate
- Which of the following nitrates will not releases brown gas when heated strongly?
A sodium nitrate
B magnesium nitrate
C lead(II) nitrate
D zinc nitrate
- What will happen if an aqueous solution of sodium chloride is added to an aqueous solution of lead(II) nitrate?
I The solution becomes acidic
II Bubbles formed
III Neutralisation reaction occurs
IV White precipitate formed
A I, II and III
B I and II
C II and IV
D IV only
Structured Question.
The figure below shows some chemical reactions on X carbonate.
X carbonate Solution Y + H2O + Gas Z
X carbonate is a green coloured powder. When added with acid R, blue coloured solution Y and gas Z that turns lime water chalky are produced.
(a) (i) Name one acid that could be R.
…………………………………………………………………………………………..
[1 mark]
- Name solution X when acid in (a)(i) is used.
…………………………………………………………………………………………..
[1 mark]
(ii) Name gas Z.
…………………………………………………………………………………………..
[1 mark]
(b) X carbonate when heated strongly will also produce gas Z and a black deposit.
(i) Draw the apparatus set-up how the experiment can be carried out in the laboratory. Show also in your diagram how the gas can be tested.
[3 marks
(ii) Write the chemical equation for the heating of X carbonate.
…………………………………………………………………………………………..
[1 marks]
(c) You are required to prepare X carbonate salt in the laboratory.
(i) Name the two substances that are required to prepare the salt.
…………………………………………………………………………………………..
[2 marks]
(ii) Name the type of reaction for the preparation of the salt above.
…………………………………………………………………………………………..
[1 mark]
Answers:
Objective Questions.
1. C 2. D 3. C 4. A 5. D
Structured Questions
- (i) sulphuric acid
(ii) copper(II) sulphate
- carbon dioxide
(b)(i)
(ii) CuCO3 → CuO + CO2
(c)(i) Copper(II) nitrate and sodium carbonate
(ii) precipitation/ double decomposition method.